#everydayquiz #20Question
Directions : In each of these questions, two equations numbered I and II with variables x and y are given. You have to solve both the equations to find the value of x and y. Give answer
1) if x > y
2) if x >= y
3) if x < y
4) if x <= y
5) if x = y or relationship between x and y cannot be determined.
1.
I. x^2 – 26x + 169 = 0
II. y^2 – 28y + 196 = 0
2.
I. 2x^2 + 6x – 36 = 0
II. 2y^2 + 25y + 78 = 0
3.
I. 7x^2 + 104x + 169 = 0
II. y^2 + 10y – 39 = 0
4.
I. x^2 – 6x – 16 = 0
II. 3y^2 + 22y + 24 = 0
Directions: Each question below is followed by two statements A and B. You have to determine whether the data given in the statement is sufficient to answer the question. You should use the data and your knowledge of mathematics to choose between the possible answers. Give answer:
1) if the statement A alone is sufficient to answer the question, but the statement B alone is not sufficient.
2) if the statement B alone is sufficient to answer the question, but the statement A alone is not sufficient.
3) if the both statement A and B together are needed to answer the question.
4) if either the statement A alone or B alone is sufficient to answer the question.
5) if you cannot get the answer from the statements A and B together, but needed even more data.
5. What is the principal?
A. The simple interest earned for 8 year at the rate of 10% p.a is Rs. 960.
B. The simple interest is Rs. 480 for 4 year.
6. The sum of the ages of P, Q, R and S is 86 year, what is Q's present age?
A. The average age of P, Q and S is 24 year.
B. The average age of R and S is 28 year.
7. In how many days, can Q alone complete the work?
A. P does 3/5 of a work in 21 days.
B. Q does 3/4 of a work in 18 days.
8. Find the number of ways in which 10 players out of 14 players can be selected such that 3 particular player are always included and 2 particular players are always excluded?
1) 38
2) 36
3) 48
4) 40
5) 32
9. The ratio of the present age of a mother and daughter is 7 : 3. Four years ago the ratio of their ages was 5 : 2. What will be the mother's age five years from now? (in years)
1) 89
2) 86
3) 87
4) 84
5) 88
10. The sum of nine consecutive odd number of set A is 657. What is the sum of seven consecutive odd numbers whose lowest number is 18 more than the lowest number of set A?
1) 620
2) 625
3) 635
4) 615
5) 623
1. 3;
I. x^2 – 26x + 169 = 0
(x – 13)^2 = 0
x = 13
II. y^2 – 28y + 196 = 0
(y – 14)^2 = 0
y = 14
x < y
2. 2;
I. 2x^2 + 12x – 6x – 36 = 0
2x (x + 6) –6 (x + 6) = 0
(x + 6) (2x – 6) = 0
x = –6, 3
II. 2y^2 + 12y + 13y + 78 = 0
2y (y + 6) + 13 (y + 6) = 0
(y + 6 ) (2y + 13) = 0
y = –6, -13/2
x > y
3. 5;
I. 7x^2 + 13x + 91x + 169 = 0
(x + 13) (7x + 13) = 0
x = – 13, -13/7
II. y^2 + 13y – 3y – 39 = 0
(y – 3) (y + 13) = 0
y = 3, – 13
Relationship between x and y cannot be established.
4. 5;
I. x^2 – 8x + 2x – 16 = 0
(x + 2) (x – 8) = 0
x = – 2, 8
II. 3y^2 + 22y + 24 = 0
3y 2 + 4y + 18y + 24 = 0
(y + 6) (3y + 4) = 0
y = –6, -4/3
Relationship between x and y cannot be established.
5. 1;
From A, we get,
P = 100*SI/R*T = Rs. 1200
5. 5;
P + Q + R + S = 86
From A, P + Q + S = 24 × 3 = 72 R = 86 – 72 = 14
From B, R + S = 28 × 2 = 56
We cannot get Q’s present age from both statements.
6. 2;
From statement B, work done by Q = 18 × 4/3 = 24 days.
7. 2;
Out of 14 players, let us element 2 particular player
which are excluded. Now, there are 12 players for selection of these 12, three have to be included in team always. Thus remaining players are (12 – 3) = 9 and the required players for team (10 – 3) = 7. Now,
selection cannot be done in
9C7 ways.
9C7 = 9!/7!2! = 36 ways.
8. 1;
Let the present age of mother and daughter be 7x and 3x year.
7x – 4/3x – 4 = 5/2
14x – 8 = 15x – 20
x = 12
Mother’s age five years from now = 12 × 7 + 5
= 84 + 5 = 89 year
9. 5;
In Set A, 9x + 2(1 + 2 + ..... + 8) = 657
9x + 8*9*2/2 = = 657
9x + 36 × 2 = 657
x = 65
lowest number of another set = 65 + 18 = 83
Sum of seven consecutive number of another set
= 7x + (1 + 2 + 3 + 4 + 5 + 6) × 2
= 7x + 6*7*2/2
= 7x + 21 = 83 × 7 + 42 = 623
10. 4;
First arrange the 7 boys in a row in 7P7 = 7! ways.
Then, there are 8 gaps between them. Now 5 girls can be
arranged in 8 gaps in P5
8 ways.
Required number of ways of arrangement = 7! × 8P5 = 7 ! * 8 !/5!
= 8! × 7 × 6 = 42 × 8 !
Directions (1-5): Study the radar graph carefully and answer the questions that follow: Number of students (in thousands) in two different universities in six different years
1.What was the difference between the number of students in university-1 in the year 2010 and the number of students in university-2 in the year 2012?
(1) Zero
(2) 5,000
(3) 15,000
(4) 10,000
(5) 1,000
2.What is the sum of the number of students in university-1 in the year 2007 and the number of students in university-2 in the year 2011 together?
(1) 48000
(2) 55000
(3) 45000
(4) 57000
(5) 40000
3.If 25% of the students in university-2 in the year 2010 were females, what was the number of male students in the university-2 in the same year?
(1) 11250
(2) 12350
(3) 12500
(4) 11500
(5) 11750
4.What was the percent increase in the number of students in university-1 in the year 2011 as compared to the previous year?
(1) 135
(2) 15
(3) 115
(4) 25
(5) 35
5.In which year was the difference between the number of students in university-1 and the number of students in university-2 highest?
(1) 2008
(2) 2009
(3) 2010
(4) 2011
(5) 2012
Directions (6-10):In the following multiple graphics, the number of selected candidates for 6 different posts by three different companies A, B and C has been shown. Read the graph carefully and answer the questions.
POST 1: HR Officer
POST 2: IT Officer
POST 3: Assistant Manager
POST 4: Advertisement Office Assistant
POST 5: Office Assistant Operations
POST 6: Junior Office Administrator
6.What is the ratio between the number of all candidates selected for company A and that selected for the posts of assistant managers and junior office administrators in all three companies?
(1) 103. : 107
(2) 102 : 107
(3) 103 : 106
(4) 113 : 117
(5)None of these
7.The number of candidates recruited for the post of office assistant operations in company B is approximately what percent of total candidates recruited in that company?
(1) 28%
(2) 24%
(3) 30%
(4) 31%
(5) None of these
8.The number of candidates recruited for the posts of assistant manager and advertisement office assistant is what per cent of the candidates recruited for the post of junior office administrator and HR officer by the company C?
(1) 115%
(2) 120%
(3) 135%
(4) 141%
(5) None of these
9.The total number of candidates recruited for the post of HR officers in all the companies is approximately what per cent of the total candidates recruited by the company A for all posts?
(1) 16%
(2) 11%
(3) 12%
(4) 14%
(5) None of these
10.What is the respective ratio between the average number of candidates selected for all the posts by company A and company C?
(1) 113 : 115
(2) 115 : 113
(3) 113 : 117
(4) 117 : 113
(5) None of these
Answers
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